4-(8x+4)^2=20

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Solution for 4-(8x+4)^2=20 equation: 



4-(8x+4)^2=20

We move all terms to the left:

4-(8x+4)^2-(20)=0

We add all the numbers together, and all the variables

-(8x+4)^2-16=0

We move all terms containing x to the left, all other terms to the right

-(8x+4)^2=16

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